X^2+71x-3162=0

Solution for X^2+71x-3162=0 equation:

X^2+71X-3162=0

a = 1; b = 71; c = -3162;
Δ = b2-4ac
Δ = 712-4·1·(-3162)
Δ = 17689
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{17689}=133$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(71)-133}{2*1}=\frac{-204}{2}
=-102
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(71)+133}{2*1}=\frac{62}{2}
=31
$